Describe how you would prepare each of the followi...

Question

Describe how you would prepare each of the following aqueous solutions, starting with solid KBr.0.80 L of 1.6×10−2 M KBr

Jules Bruno · Accepted Answer

We’re being asked to determine the amount of KBr needed to prepare 0.80 L of 1.6x10-2 M KBr.Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:Molarity(M)=moles of soluteLiters of solution[readmore]The flow for this problem will be like this:Volume of solution (molarity of KBr) → Moles of KBr (molar mass of KBr) → Mass of KBrWe will do the following steps to solve the problem:Step 1: Calculate the moles of KBrStep 2: Calculate the mass of KBr[readmore]Step 1: Calculate the moles of KBrWe can calculate the moles of KBr from the given molarity of the solution.We have1.6x10-2 M KBr0.80 L KBrThe moles of solute or moles of KBr ismolarity KBr = moles KBrLiters H2O1.6×10-2 M×0.80 L= moles KBr0.80 L×0.80 Lmoles KBr = 1.6×10-2 molL × 0.80 L*M = mol/Lmoles KBr = 0.0128Step 2: Calculate the mass of KBrWe calculate the amount of KBr needed to prepare the solution from the moles of KBr and its molar mass.The molar mass of KBr isKBr          1 x 39.1 g/mol K = 39.1 g/mol                1 x 79.9 g/mol Br = 79.9 g/mol             ---------------------------------------------                                      Sum = 119 g/molWe have 0.0128 mol KBrThe mass of KBr needed is0.0128 mol KBr ×119 g KBr1 mol KBr= 1.52 g KBrThe 1.6x10-2 M KBr solution can be prepared by dissolving 1.52 g KBr in 0.80 L H2O.

Problem: Describe how you would prepare each of the following aqueous solutions, starting with solid KBr.0.80 L of 1.6×10−2 M KBr

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Problem Details

Problem: Describe how you would prepare each of the following aqueous solutions, starting with solid KBr.0.80 L of 1.6×10−2 M KBr

FREE Expert Solution

Problem Details

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