We’re being asked to determine the **amount of KBr** needed to prepare 0.80 L of 1.6x10^{-2} M KBr.

Recall that ** molarity** is the ratio of the moles of solute and the volume of solution (in liters).

In other words:

$\overline{){\mathbf{Molarity}}{\mathbf{\left(}}{\mathbf{M}}{\mathbf{\right)}}{\mathbf{=}}\frac{\mathbf{moles}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solute}}{\mathbf{Liters}\mathbf{}\mathbf{of}\mathbf{}\mathbf{solution}}}$

Describe how you would prepare each of the following aqueous solutions, starting with solid KBr.

0.80 L of 1.6×10^{−2} M KBr

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