We’re being asked to calculate the molarity (M) of 0.550 g Mg(NO3)2 in 250.0 mL of solution. Recall that molarity is the ratio of the moles of solute and the volume of solution (in liters). In other words:
We first need to determine the number of moles of Mg(NO3)2. We’re given the mass of Mg(NO3)2, 0.550 g. We can get the moles through the following:
mass of Mg(NO3)2 (molar mass of Mg(NO3)2) → moles of Mg(NO3)2
Calculate the molarity of the following aqueous solutions.
0.550 g Mg(NO3 )2 in 250.0 mL of solution
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