Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Pick an appropriate solvent from the table below to dissolve each substance. State the kind of intermolecular forces that would occur between the solute and solvent in each case.Common polar solventsC

Solution: Pick an appropriate solvent from the table below to dissolve each substance. State the kind of intermolecular forces that would occur between the solute and solvent in each case.Common polar solventsC

Problem
Pick an appropriate solvent from the table below to dissolve each substance. State the kind of intermolecular forces that would occur between the solute and solvent in each case.


Common polar solventsCommon nonpolar solvents
Water (H2O)Hexane (C6H14)
Acetone (CH3COCH3)Diethyl ether (CH3CH2OCH2CH3)
Methanol (CH3OH)Toluene (C7H8)
Ethanol (CH3CH2OH)Carbon tetrachloride (CCl4)


Pick appropriate solvent(s) to dissolve paraffin oil (nonpolar).

Solution

We’re being asked in which appropriate solvent would dissolve paraffin oil. 


Recall that the main idea in dissolution is like dissolves like, which means compounds with the same polarity and intermolecular force can dissolve each other.


Paraffin oil is an example of a hydrocarbon, a compound composed only of carbons and hydrogens. 

Hydrocarbons are nonpolar compounds. This means that paraffin oil is a nonpolar molecule that exhibits dispersion forces.


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