We’re being asked in which appropriate solvent would dissolve paraffin oil.
Recall that the main idea in dissolution is like dissolves like, which means compounds with the same polarity and intermolecular force can dissolve each other.
Paraffin oil is an example of a hydrocarbon, a compound composed only of carbons and hydrogens.
Hydrocarbons are nonpolar compounds. This means that paraffin oil is a nonpolar molecule that exhibits dispersion forces.
|Common polar solvents||Common nonpolar solvents|
|Water (H2O)||Hexane (C6H14)|
|Acetone (CH3COCH3)||Diethyl ether (CH3CH2OCH2CH3)|
|Methanol (CH3OH)||Toluene (C7H8)|
|Ethanol (CH3CH2OH)||Carbon tetrachloride (CCl4)|
Pick appropriate solvent(s) to dissolve paraffin oil (nonpolar).
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Solutions, Molarity and Intermolecular Forces concept. You can view video lessons to learn Solutions, Molarity and Intermolecular Forces. Or if you need more Solutions, Molarity and Intermolecular Forces practice, you can also practice Solutions, Molarity and Intermolecular Forces practice problems.
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Based on our data, we think this problem is relevant for Professor Kijewska & Pollock's class at MSU.