Recall:
Given:
mass percent = 12.5% NaNO3 solution
density = 1.02 g/mL
Recall:
This means: 12.5 g NaNO3 g in 100 g solution
A sodium nitrate solution is 12.5 % NaNO3 by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.
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