Problem: A sodium nitrate solution is 12.5 % NaNO3 by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.

FREE Expert Solution

Recall:

Molarity (M)=moles of soluteLiters of solution


Given:

mass percent = 12.5% NaNO3 solution

density = 1.02 g/mL


Recall:

% Mass=mass of NaNO3mass of solution×100


This means: 12.5 g NaNO3 g in 100 g solution

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Problem Details

A sodium nitrate solution is 12.5 % NaNO3 by mass and has a density of 1.02 g/mL. Calculate the molarity of the solution.

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