Problem: How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?126 mL of 0.115 M NaNO3

We are asked how much dry solute would be needed to prepare 126 mL of 0.115 M NaNO₃

Recall: 

$\boxed{\mathbf{Molarity}\mathbf{ }\mathbf{=}\frac{\mathbf{ }\mathbf{mol}\mathbf{ }\mathbf{solute}\mathbf{ }}{\mathbf{L}\mathbf{ }\mathbf{solution}}}$

We go through the following steps to solve the problem:

Step 1. Calculate the molar mass of the solute

Step 2. Calculate the moles solute

Step 3. Calculate the mass solute