We are asked how **much dry solute would be needed to prepare 126 mL of 0.115 M NaNO**_{3}

Recall:

$\overline{){\mathbf{Molarity}}{\mathbf{}}{\mathbf{=}}\frac{\mathbf{}\mathbf{mol}\mathbf{}\mathbf{solute}\mathbf{}}{\mathbf{L}\mathbf{}\mathbf{solution}}}$

**We go through the following steps to solve the problem:**

**Step 1.** Calculate the molar mass of the solute

**Step 2. **Calculate the moles solute

**Step 3.** Calculate the mass solute

How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?

126 mL of 0.115 M NaNO_{3}