We’re being asked to calculate for the molality of *an aqueous solution prepared by dissolving 126 g NaCl in a total volume of 1.15 L. *

When calculating for molality, we use the following equation:

$\overline{){\mathbf{molality}}{\mathbf{}}\mathbf{\left(}\mathbf{m}\mathbf{\right)}{\mathbf{=}}\frac{\mathbf{mol}\mathbf{}\mathbf{solute}}{\mathbf{kg}\mathbf{}\mathbf{solvent}}\mathbf{}}$

*Aqueous solution → water is the solvent*

*Solute → NaCl*

**We will calculate the molality of the solution using the following steps:**

*Step 1: **Calculate the moles of solute*

*Step 2**. Calculate the mass of the solvent (in kg).Step 3. Calculate the molality of the solution.*

An aqueous NaCl solution is made using 126 g of NaCl diluted to a total solution volume of 1.15 L .

Calculate the molality of the solution. (Assume a density of 1.08 g/mL for the solution.)

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