Unknown Kp value: H2O (g) + ½ O2 (g) ⇌ H2O2 (g) K = ?
Reaction 1: H2 (g) + O2 (g) ⇌ H2O2 (g) K1 = 2.3 x 106
Reaction 2: 2 H2 (g)+ O2 (g) ⇌ 2 H2O (g) K2 = 1.8 x 1037
Reaction 1: H2O2(g) is in the product side so no changes needed.
H2 (g) + O2 (g) ⇌ H2O2 (g) K1 = 2.3 x 106
Reaction 2: H2O(g) is in the reactant side with a different coefficient. We need to reverse the reaction and multiply it by 1/2:
When reversing a reaction → get the reciprocal of Kp (1/Kp)
Calculate ΔG° for H2O(g) + 1/2O2(g) ⇌ H2O2 (g) at 600. K, using the following data:
H2(g) + O2(g) ⇌ H2O2 (g) K = 2.3 X 10 6 at 600. K
2H2(g) + O2( g) ⇌ 2H 2O(g) K = 1.8 X 10 37 at 600. K
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