# Problem: Calculate ΔG° for H2O(g) + 1/2O2(g) ⇌ H2O2 (g) at 600. K, using the following data:H2(g) + O2(g) ⇌ H2O2 (g)              K = 2.3 X 10  6 at 600. K2H2(g) + O2( g) ⇌ 2H 2O(g)            K = 1.8 X 10  37 at 600. K

###### FREE Expert Solution

Given reactions:

Unknown Kvalue:    H2O (g) + ½ O2 (g)  H2O2 (g)                       K = ?

Reaction 1:                 H(g) + O2 (g) ⇌ H2O2 (g)                                K1 = 2.3 x 106

Reaction 2:                  2 H (g)+ O2 (g) ⇌ 2 H2O (g)                           K2 = 1.8 x 1037

Reaction 1: H2O2(g) is in the product side so no changes needed.

H(g) + O2 (g) ⇌ H2O2 (g)                     K1 = 2.3 x 106

Reaction 2: H2O(g) is in the reactant side with a different coefficient.  We need to reverse the reaction and multiply it by 1/2

When reversing a reaction  get the reciprocal of Kp (1/Kp)

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###### Problem Details

Calculate ΔG° for H2O(g) + 1/2O2(g) ⇌ H2O2 (g) at 600. K, using the following data:

H2(g) + O2(g) ⇌ H2O2 (g)              K = 2.3 X 10  6 at 600. K

2H2(g) + O2( g) ⇌ 2H 2O(g)            K = 1.8 X 10  37 at 600. K