Problem: Given the following data:2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l) ΔG° = -6399 kJC (s) + O2 (g) → CO2 (g) ΔG° = -394 kJH2 (g) + 1/2O2 (g) → H2O (l) ΔG° = -237 kJcalculate ΔG° for the reaction6C (s) + 3H2 (g) → C6H6 (l)
FREE Expert Solution
Given:
2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l) ΔG° = -6399 kJ
C (s) + O2 (g) → CO2 (g) ΔG° = -394 kJ
H2 (g) + 1/2O2 (g) → H2O (l) ΔG° = -237 kJ
Overall Reaction: 6C (s) + 3H2 (g) → C6H6 (l)
Rearrange the reaction and adjust the ΔG° value accordintly:
- 2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l) ΔG° = -6399 kJ
Reverse the reaction, divide by 2, and change the sign of ΔG°:
6CO2 (g) + 3H2O (l) → C6H6 (l) + 15/2O2 (g) ΔG° = 6399 kJ/2 = 3199.5 kJ
- C (s) + O2 (g) → CO2 (g) ΔG° = -394 kJ
Multiply the reaction and ΔG° by 6:
6C (s) + 6O2 (g) → 6CO2 (g) ΔG° = 6(-394 kJ) = -2364 kJ
- H2 (g) + 1/2O2 (g) → H2O (l) ΔG° = -237 kJ
Multiply the reaction and ΔG° by 3:
3H2 (g) + O2 (g) → 3 H2O (l) ΔG° = 3(-237 kJ) = -711 kJ
Adding the reaction:
Problem Details
Given the following data:
2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6H2O (l) ΔG° = -6399 kJ
C (s) + O2 (g) → CO2 (g) ΔG° = -394 kJ
H2 (g) + 1/2O2 (g) → H2O (l) ΔG° = -237 kJ
calculate ΔG° for the reaction
6C (s) + 3H2 (g) → C6H6 (l)
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