Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Two concentration cells are prepared, both with 90.0 mL of 0.0100 M Cu(NO 3)2 and a Cu bar in each half-cell.(c) In the second concentration cell, 10.0 mL of 0.500 M NaOH is added to one half-cell; th

Problem

Two concentration cells are prepared, both with 90.0 mL of 0.0100 M Cu(NO 3)2 and a Cu bar in each half-cell.

(c) In the second concentration cell, 10.0 mL of 0.500 M NaOH is added to one half-cell; the precipitate Cu(OH)2 forms (Ksp = 2.2 × 10−20). Calculate E°cell.