Ch.18 - ElectrochemistryWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: From the skeleton equations below, create a list of balanced half-reactions in which the strongest oxidizing agent is on top and the weakest is on the bottom:U3+(aq) + Cr3+(aq) ⟶ Cr2+(aq) + U4+(aq) Fe(s) + Sn2+(aq) ⟶ Sn(s) + Fe2+(aq) Fe(s) + U4+(aq) ⟶ no reaction Cr3+(aq) + Fe(s) ⟶ Cr 2+(aq) + Fe2+(aq)  Cr2+(aq) + Sn2+(aq) ⟶ Sn(s) + Cr 3+(aq)

Solution: From the skeleton equations below, create a list of balanced half-reactions in which the strongest oxidizing agent is on top and the weakest is on the bottom:U3+(aq) + Cr3+(aq) ⟶ Cr2+(aq) + U4+(aq)Fe(

Problem

From the skeleton equations below, create a list of balanced half-reactions in which the strongest oxidizing agent is on top and the weakest is on the bottom:

U3+(aq) + Cr3+(aq) ⟶ Cr2+(aq) + U4+(aq)
Fe(s) + Sn2+(aq) ⟶ Sn(s) + Fe2+(aq)
Fe(s) + U4+(aq) ⟶ no reaction
Cr3+(aq) + Fe(s) ⟶ Cr 2+(aq) + Fe2+(aq) 
Cr2+(aq) + Sn2+(aq) ⟶ Sn(s) + Cr 3+(aq)