We’re being asked to determine thedetermine the solubility product, Ksp, for PbCl2(s).
PbCl2(s) ⇌ Pb2+(aq) + 2 Cl −(aq)
Recall that ΔG˚rxn and K are related to each other:
We can use the following equation to solve for ΔG˚rxn:
Step 1: We can easily solve for ΔG˚rxn.
ΔG f ° for Pb2+(aq) = −24.3 kJ/mol
ΔG f ° for Cl −(aq) = −131.2 kJ/mol
ΔG f ° for Cl −(aq) = −314.2 kJ/mol
ΔG˚rxn = 27.5 kJ
Given that the ΔG f ° for Pb2+(aq) and Cl −(aq) is −24.3 kJ/mole and −131.2 kJ/mole respectively, determine the solubility product, Ksp, for PbCl2(s).
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