Problem: A voltaic cell is constructed with a Cu/Cu2+ half-cell and an Ni/Ni2+ half-cell. The nickel electrode is negative.(b) Diagram the cell, labeling electrodes with their charges and showing the directions of electron flow in the circuit and of cation and anion flow in the salt bridge.

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FREE Expert Solution

 Anode is in the negative side (left side of the diagram)

▪ Anode → oxidation
oxidation half-reaction happens in the anode solution
▪ losing electrons → becoming more positive → anode dissolves away

 Cathode is in the positive side (right side of the diagram)

▪ Cathode → reduction
reduction half-reaction happens in the anode solution
▪ gaining electrons → becoming more negative → solids is deposited in the surface

 Electrons flow from the anode cell to the cathode cell through a wire.

Cu2+(aq) + 2 e → Cu(s)                    E° = +0.3419       ↑ E° → reduction → cathode

Ni2+(aq) + 2 e → Ni(s)                       E° = ‒0.257        ↓ E° → oxidation → anode

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Problem Details

A voltaic cell is constructed with a Cu/Cu2+ half-cell and an Ni/Ni2+ half-cell. The nickel electrode is negative.

(b) Diagram the cell, labeling electrodes with their charges and showing the directions of electron flow in the circuit and of cation and anion flow in the salt bridge.

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Our tutors have indicated that to solve this problem you will need to apply the Galvanic Cell concept. You can view video lessons to learn Galvanic Cell Or if you need more Galvanic Cell practice, you can also practice Galvanic Cell practice problems .

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