Anode is in the negative side (left side of the diagram)
▪ Anode → oxidation
▪ oxidation half-reaction happens in the anode solution
▪ losing electrons → becoming more positive → anode dissolves away
Cathode is in the positive side (right side of the diagram)
▪ Cathode → reduction
▪ reduction half-reaction happens in the anode solution
▪ gaining electrons → becoming more negative → solids is deposited in the surface
Electrons flow from the anode cell to the cathode cell through a wire.
Cu2+(aq) + 2 e– → Cu(s) E° = +0.3419 ↑ E° → reduction → cathode
Ni2+(aq) + 2 e– → Ni(s) E° = ‒0.257 ↓ E° → oxidation → anode
A voltaic cell is constructed with a Cu/Cu2+ half-cell and an Ni/Ni2+ half-cell. The nickel electrode is negative.
(b) Diagram the cell, labeling electrodes with their charges and showing the directions of electron flow in the circuit and of cation and anion flow in the salt bridge.
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.