Ag+ (aq) + e- → Ag (s) E° = 0.80 V ↑ E° → reduction → cathode
Pb2+ (aq) + 2 e- → Pb (s) E° = -0.13 V ↓ E° → oxidation → anode
cathode: [Ag (s) → Ag+ (aq) + e-] x 2
anode: Pb2+ (aq) + 2 e- → Pb (s)
A voltaic cell is constructed with an Ag/Ag+ half-cell and a Pb/Pb2+ half-cell. The silver electrode is positive.
(a) Write balanced half-reactions and the overall cell reaction.
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.