Problem: Alabandite is a mineral composed of manganese(II) sulfide (MnS). The mineral adopts the rock salt structure. The length of an edge of the MnS unit cell is 5.223 Å at 25˚C. Determine the density of MnS in g/cm3 m g/cm^3.

FREE Expert Solution

Step 1

$mass = \frac{4 atoms MnS}{1 unit cell} \times \frac{1 mol MnS}{6.022 \times 10^{23} atoms MnS} \times \frac{87.004 g MnS}{1 mol MnS}$

mass = 5.78x10^-22 g MnS/ unit cell

Step 2

$volume = a^{3} volume = {(2 \sqrt{2} \cdot r)}^{3} volume = {(2 \sqrt{2} \times 5.223 Å \times \frac{10^{- 10} m}{1 Å} \times \frac{1 cm}{10^{- 2} m})}^{3}$

volume = 3.224x10^-21 cm³

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Problem Details

Alabandite is a mineral composed of manganese(II) sulfide (MnS). The mineral adopts the rock salt structure. The length of an edge of the MnS unit cell is 5.223 Å at 25˚C. Determine the density of MnS in g/cm³ m g/cm^3.

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Problem: Alabandite is a mineral composed of manganese(II) sulfide (MnS). The mineral adopts the rock salt structure. The length of an edge of the MnS unit cell is 5.223 Å at 25˚C. Determine the density of MnS in g/cm3 m g/cm^3.

FREE Expert Solution

Problem Details

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