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Problem: In the unit cell drawing on the right, why do we see eight Sm atoms and nine Co atoms if the empirical formula is SmCo5?

FREE Expert Solution

Atoms on the corner → equally shared by 8 unit cells → Hence they contribute 1/8 to one unit cell

Atoms on the faces → equally shared by 2 unit cells → Hence they contribute 1/2 to one unit cell

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Problem Details

In the unit cell drawing on the right, why do we see eight Sm atoms and nine Co atoms if the empirical formula is SmCo5?

Ni3Al has Al atoms as the corners of a cube. Within the cube are Ni atoms. Nb3Sn has Sn atoms as the corners of a cube. Within the cube are Nb atoms. SmCo5 has Sm atoms as the corners of a cube. Within the cube are 9 Co atoms.


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Based on our data, we think this problem is relevant for Professor Bindell's class at UCF.