We are asked to **identify the coordination number of the anion in MgS**.

We are given that the **coordination number for Mg ^{2+} ion is usually six** and this assumption holds. To answer this, we shall use the following equation:

$\overline{){\mathbf{Anion}}{\mathbf{}}{\mathbf{C}}{\mathbf{.}}{\mathbf{N}}{\mathbf{.}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{Cation}}{\mathbf{}}{\mathbf{C}}{\mathbf{.}}{\mathbf{N}}{\mathbf{.}}{\mathbf{\left(}}\frac{\mathbf{\#}\mathbf{}\mathbf{of}\mathbf{}\mathbf{cations}\mathbf{}\mathbf{per}\mathbf{}\mathbf{formula}\mathbf{}\mathbf{unit}}{\mathbf{\#}\mathbf{}\mathbf{of}\mathbf{}\mathbf{anions}\mathbf{}\mathbf{per}\mathbf{}\mathbf{formula}\mathbf{}\mathbf{unit}}{\mathbf{\right)}}}$

Where: C.N. = Coordination Number

The coordination number for Mg^{2+} ion is usually six. Assuming this assumption holds, determine the anion coordination number in the following compounds.

MgS

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