Calculate Oxidation Numbers Video Lessons

Video Thumbnail

Concept:

Problem: Replacement of aluminum ions in kaolinite with magnesium ions yields a compound with the formula Mg3Si2O5(OH)4. Assign an oxidation state to each element in this compound.What is the oxidation state of Mg in Mg3Si2O5(OH)4?

FREE Expert Solution

We’re being asked to determine the oxidation state of Mg in Mg3Si2O5(OH)4


The rules for oxidation states are as follows:


A. General Rules:

1. For an atom in its elemental form (Zn, Cl2, C(graphite), etc.)    O.S. = 0

2. For an ion (Li+, Al3+, etc.)                                                       O.S. = charge


B. Specific Rules:

1. Group 1A              O.S. = +1

2. Group 2A              O.S. = +2

3. Hydrogen              O.S. = +1, with nonmetals

                                  O.S. = –1 with metals and boron

4. Fluorine                 O.S. = –1

5. Oxygen                  O.S. = –1 in peroxides (X2O2, X = Group 1A)

                                  O.S. = –1/2 in superoxides (XO2, X = Group 1A)

                                  O.S. = –2 in other compounds

6. Group 7A               O.S. = –1 (except when bonded to O)


96% (408 ratings)
View Complete Written Solution
Problem Details

Replacement of aluminum ions in kaolinite with magnesium ions yields a compound with the formula Mg3Si2O5(OH)4. Assign an oxidation state to each element in this compound.

What is the oxidation state of Mg in Mg3Si2O5(OH)4?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Calculate Oxidation Numbers concept. You can view video lessons to learn Calculate Oxidation Numbers. Or if you need more Calculate Oxidation Numbers practice, you can also practice Calculate Oxidation Numbers practice problems.