We’re being asked to determine the oxidation state of Mg in Mg3Si2O5(OH)4
The rules for oxidation states are as follows:
A. General Rules:
1. For an atom in its elemental form (Zn, Cl2, C(graphite), etc.) O.S. = 0
2. For an ion (Li+, Al3+, etc.) O.S. = charge
B. Specific Rules:
1. Group 1A O.S. = +1
2. Group 2A O.S. = +2
3. Hydrogen O.S. = +1, with nonmetals
O.S. = –1 with metals and boron
4. Fluorine O.S. = –1
5. Oxygen O.S. = –1 in peroxides (X2O2, X = Group 1A)
O.S. = –1/2 in superoxides (XO2, X = Group 1A)
O.S. = –2 in other compounds
6. Group 7A O.S. = –1 (except when bonded to O)
Replacement of aluminum ions in kaolinite with magnesium ions yields a compound with the formula Mg3Si2O5(OH)4. Assign an oxidation state to each element in this compound.
What is the oxidation state of Mg in Mg3Si2O5(OH)4?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Calculate Oxidation Number concept. If you need more Calculate Oxidation Number practice, you can also practice Calculate Oxidation Number practice problems.