🤓 Based on our data, we think this question is relevant for Professor Roychowdhury's class at RUTGERS.
There are 9 titanium atoms in the structure of which eight are at the corners of the unit cell and one in the center.
Contribution of one atom at the corner: 1/8
There are 8 atoms hence
Contribution of 1 atom at the center: 1
Total number titanium atoms: 2
There are 6 oxygen atoms in the structure, four of which are at the face centers and two are close to the center.
In face centers, the contribution is 1/2
Therefore the number of oxygen atoms is:
An oxide of titanium crystallizes with the following unit cell (titanium = gray; oxygen = red)
What is the formula of the oxide?
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Based on our data, we think this problem is relevant for Professor Roychowdhury's class at RUTGERS.