🤓 Based on our data, we think this question is relevant for Professor Roychowdhury's class at RUTGERS.

There are 9 titanium atoms in the structure of which eight are at the corners of the unit cell and one in the center.

Contribution of one atom at the corner: 1/8

There are 8 atoms hence

$\mathbf{8}\mathbf{\times}\frac{\mathbf{1}}{\mathbf{8}}\mathbf{=}$**1**

Contribution of 1 atom at the center:** 1**

**Total number titanium atoms: 2**

There are 6 oxygen atoms in the structure, four of which are at the face centers and two are close to the center.

In face centers, the contribution is 1/2

Therefore the number of oxygen atoms is:

$(2\times 1)\mathbf{+}(4\times \frac{1}{2})\mathbf{=}$**4**

An oxide of titanium crystallizes with the following unit cell (titanium = gray; oxygen = red)

.

What is the formula of the oxide?

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Based on our data, we think this problem is relevant for Professor Roychowdhury's class at RUTGERS.