Problem: The human body obtains ​950 kJ of energy from a candy bar.If this energy were used to vaporize water at 100.0 oC​, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)

FREE Expert Solution

We have to determine how many liters of water at 100 °C can be evaporated by absorption of 950 kJ of heat.


The amount of heat required for a substance to evaporate at its boiling point is given by this formula:

qvap = m·Hvap

Where,

qvap = amount of heat required for evaporation

m = mass of substance

ΔHvap = latent heat of vaporization

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Problem Details

The human body obtains 950 kJ of energy from a candy bar.

If this energy were used to vaporize water at 100.0 oC, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Heating and Cooling Curves concept. You can view video lessons to learn Heating and Cooling Curves. Or if you need more Heating and Cooling Curves practice, you can also practice Heating and Cooling Curves practice problems.