We have to determine how many liters of water at 100 °C can be evaporated by absorption of 950 kJ of heat.

The **amount of heat** required for a substance to evaporate at its boiling point is given by this formula:

$\overline{){{\mathbf{q}}}_{{\mathbf{vap}}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{m}}{\mathbf{\xb7}}{\mathbf{\u2206}}{{\mathbf{H}}}_{{\mathbf{vap}}}}$

**Where,**

q_{vap} = amount of heat required for evaporation

m = mass of substance

ΔH_{vap} = latent heat of vaporization

The human body obtains 950 kJ of energy from a candy bar.

If this energy were used to vaporize water at 100.0 ^{o}C, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)

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