🤓 Based on our data, we think this question is relevant for Professor Sadighi's class at GT.
The Lewis structure of aspartame is:
The hybridization of an atom can be determined by the number of electron groups around it. Electron groups include bond pairs and lone pairs.
4 groups → AX4 notation → 4 hybrid orbitals → sp3 hybridization
3 groups → AX3 notation → 3 hybrid orbitals → sp2 hybridization
2 groups → AX2 notation → 2 hybrid orbitals → sp hybridization
Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below.
Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C6H5). Benzene is discussed in Section 4‑7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp2 hybridization? How many C and O atoms exhibit sp3 hybridization? How many σ and π bonds are in aspartame?
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Orbital Overlap concept. If you need more Orbital Overlap practice, you can also practice Orbital Overlap practice problems.
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Based on our data, we think this problem is relevant for Professor Sadighi's class at GT.
What textbook is this problem found in?
Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.