Ch.10 - Molecular Shapes & Valence Bond TheoryWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Consider three molecules: A, B, and C. Molecule A has a hybridization of sp 3. Molecule B has two more effective pairs (electron pairs around the central atom) than molecule A. Molecule C consists of two σ bonds and two π bonds. Give the molecular structure, hybridization, bond angles, and an example for each molecule.

Solution: Consider three molecules: A, B, and C. Molecule A has a hybridization of sp 3. Molecule B has two more effective pairs (electron pairs around the central atom) than molecule A. Molecule C consists of

Problem

Consider three molecules: A, B, and C. Molecule A has a hybridization of sp 3. Molecule B has two more effective pairs (electron pairs around the central atom) than molecule A. Molecule C consists of two σ bonds and two π bonds. Give the molecular structure, hybridization, bond angles, and an example for each molecule.

Solution
  • For molecule A, Recall that an sp3 hybridized atom has 4 regions of electron density. This electron density could either be a lone pair or bonding electrons. 
  • Methane (CH4) is a good example of this. 
  • C will appear as central atom with 4 Hs on it. Valence electrons of C is 4, H is 1. Total v.e is 16. 12+(4)1 = 16e-

  • CH4 follows a tetrahedral setup with 109.5bond angle. 
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