Problem: Consider the following reaction:A2 + B2 → 2AB ΔE = -285 kJThe bond energy for A2 is one-half the amount of the AB bond energy. The bond energy of B 2 = 432 kJ/mol. What is the bond energy of A2?

ΔE or ΔH can be calculated as:

$∆ H = bond {energy}_{reactants} - bond {energy}_{products} ∆ H = (BE A_{2} + BE B_{2}) - 2 (BE AB)$

If A₂ is half the amount of AB, we can set up the equation as:

97% (306 ratings)

Consider the following reaction:

A₂ + B₂→ 2AB ΔE = -285 kJ

The bond energy for A₂ is one-half the amount of the AB bond energy. The bond energy of B ₂ = 432 kJ/mol. What is the bond energy of A₂?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Bond Energy concept. You can view video lessons to learn Bond Energy. Or if you need more Bond Energy practice, you can also practice Bond Energy practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Kumar's class at Adelphi University.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.