Ch.9 - Bonding & Molecular StructureWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Sections
Chemical Bonds
Lattice Energy
Lattice Energy Application
Born Haber Cycle
Dipole Moment
Lewis Dot Structure
Octet Rule
Formal Charge
Resonance Structures
Additional Practice
Bond Energy

Solution: Oxidation of the cyanide ion produces the stable cyanate ion, OCN-. The fulminate ion, CNO-, on the other hand, is very unstable. Fulminate salts explode when struck; Hg(CNO)2 is used in blasting caps

Solution: Oxidation of the cyanide ion produces the stable cyanate ion, OCN-. The fulminate ion, CNO-, on the other hand, is very unstable. Fulminate salts explode when struck; Hg(CNO)2 is used in blasting caps

Problem

Oxidation of the cyanide ion produces the stable cyanate ion, OCN-. The fulminate ion, CNO-, on the other hand, is very unstable. Fulminate salts explode when struck; Hg(CNO)2 is used in blasting caps. Write the Lewis structures and assign formal charges for the cyanate and fulminate ions. Why is the fulminate ion so unstable? (C is the central atom in OCN- and N is the central atom in CNO-.)

Solution

Both structures have the same charge and elements so the number of valence electrons will be the same. Valence electrons will be based on the group number of each element. Remember that we have to add 1 more electron for the negative charge. 


The two ions would only differ in the way they are connected.

View the complete written solution...