Ch.9 - Bonding & Molecular StructureWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Sections
Chemical Bonds
Lattice Energy
Lattice Energy Application
Born Haber Cycle
Dipole Moment
Lewis Dot Structure
Octet Rule
Formal Charge
Resonance Structures
Additional Practice
Bond Energy

Solution: Benzoic acid is a food preservative. The space-filling model for benzoic acid is shown below.Draw the Lewis structure for benzoic acid, including all resonnance structures in which all atoms have a fo

Solution: Benzoic acid is a food preservative. The space-filling model for benzoic acid is shown below.Draw the Lewis structure for benzoic acid, including all resonnance structures in which all atoms have a fo

Problem

Benzoic acid is a food preservative. The space-filling model for benzoic acid is shown below.


Draw the Lewis structure for benzoic acid, including all resonnance structures in which all atoms have a formal charge of zero

Solution
  • We can make an initial Lewis structure out of the given space-filling mode where benzoic acid appears to have 6 Cs atoms in a ring-like structure with 5 Hs on it. The last C atom has a -CO2H group on it

  • Now account for the electrons in the structure to by determining how many valence electrons are present.

  • C atoms have 4 valence electrons, while H has 1 and O has 6. Total valence electrons are 46 (4(7) + 6(2) + 1(6) = 46)

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