The more energetically stable compound is, the lower energy it has. We will look at how the compounds are formed to determine which is more stable.
Comparing the two compounds, both NaBr and NaBr2 have ionic bonds. Ionic bond is formed from the transfer of valence electrons from a metal to a non-metal. In this case, Na is our metal and Br is our non-metal.
Let us determine the valence electrons of our metal and non-metal:
Which member of the following pairs would you expect to be more energetically stable? Justify each choice.
a. NaBr or NaBr 2
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Our tutors have indicated that to solve this problem you will need to apply the Lewis Dot Structures: Sigma & Pi Bonds concept. You can view video lessons to learn Lewis Dot Structures: Sigma & Pi Bonds. Or if you need more Lewis Dot Structures: Sigma & Pi Bonds practice, you can also practice Lewis Dot Structures: Sigma & Pi Bonds practice problems.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl Atoms 1st 2nd Edition practice problems.