Problem: Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH  3CH2)3N (Kb = 5.2 × 10−4), with 0.1000 M HCl solution after the following additions of titrant:(c) 15.00 mL

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FREE Expert Solution

Reaction:

(CH3CH2)3N(aq) + HCl(aq) → (CH3CH2)3NH+(aq) + Cl-(aq)


Step 1: Calculate the initial amount (in moles) of each species:

Given:

20.00 mL of 0.1000 M (CH3CH2)3N
15 mL of 0.1000 M HCl


molarity (M)=molL

moles (CH3CH2)3N=(0.1000mol (CH3CH2)3NL) (20.00 mL x 10-3 L1 mL)

(CH3CH2)3N = 0.002 mol NH3

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Problem Details

Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH  3CH2)3N (Kb = 5.2 × 10−4), with 0.1000 M HCl solution after the following additions of titrant:

(c) 15.00 mL