🤓 Based on our data, we think this question is relevant for Professor Weems' class at Johnson County Community College.
(CH3CH2)3N(aq) + HCl(aq) → (CH3CH2)3NH+(aq) + Cl-(aq)
Step 1: Calculate the initial amount (in moles) of each species:
• 20.00 mL of 0.1000 M (CH3CH2)3N
• 15 mL of 0.1000 M HCl
(CH3CH2)3N = 0.002 mol NH3
Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH 3CH2)3N (Kb = 5.2 × 10−4), with 0.1000 M HCl solution after the following additions of titrant:
(c) 15.00 mL