(CH3CH2)3N(aq) + HCl(aq) → (CH3CH2)3NH+(aq) + Cl-(aq)
Step 1: Calculate the initial amount (in moles) of each species:
• 20.00 mL of 0.1000 M (CH3CH2)3N
• 15 mL of 0.1000 M HCl
(CH3CH2)3N = 0.002 mol NH3
Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH 3CH2)3N (Kb = 5.2 × 10−4), with 0.1000 M HCl solution after the following additions of titrant:
(c) 15.00 mL
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Weak Base Strong Acid Titrations concept. You can view video lessons to learn Weak Base Strong Acid Titrations. Or if you need more Weak Base Strong Acid Titrations practice, you can also practice Weak Base Strong Acid Titrations practice problems.
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Based on our data, we think this problem is relevant for Professor Weems' class at Johnson County Community College.
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Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.