Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Liquid ammonia autoionizes like water:2NH3(l) ⟶ NH4+(am) + NH2−(am)where (am) represents solvation by NH3.(e) Pure sulfuric acid also autoionizes. Write the ion-product constant expression,  Ksulf, an

Problem

Liquid ammonia autoionizes like water:

2NH3(l) ⟶ NH4+(am) + NH2(am)

where (am) represents solvation by NH3.

(e) Pure sulfuric acid also autoionizes. Write the ion-product constant expression,  Ksulf, and find the concentration of the conjugate base at 20°C (Ksulf = 2.7 x 10−4 at 20°C).