Recall that strong base completely dissociates in water and that base accepts H+ from acid (water in this case). The dissociation of Ba(OH)2 is as follows:
Ba(OH)2(aq) + H2O(l) → Ba2+(aq) + 2 OH–(aq)
(b) What is the pOH of 2.55 M Ba(OH)2? Is the solution neutral, acidic, or basic?
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