Problem: (b) What is the pOH of 1.35×10−3 M HCl? Is the solution neutral, acidic, or basic?

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HClstrong acid


Since sulfuric acid is a strong acid, it will completely dissociate in the solution:

HCl(aq) → H+(aq) + Cl-(aq)


Ratio:             1 mol of HCl produces 1 mol of H+


[H+] = [HCl]
[H+] = 1.35×10−3 M


pH=-log H+pH=-log 1.35×10-3 M

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(b) What is the pOH of 1.35×10−3 M HCl? Is the solution neutral, acidic, or basic?