Problem: (b) What is the pH of 0.88 M pyridinium chloride, C 5H5NHCl?

🤓 Based on our data, we think this question is relevant for Professor Davis' class at UCF.

FREE Expert Solution

C5H5NHCl → C5H5NH+ + Cl-

C5H5NH+ → positively charged amine → weak acid


C5H5NH+ + H2O → C5H5NH + H3O+


Kb for C5H5NH =  1.7x10-9

Kw=Ka·Kb

Assuming the reaction is at 25°C:             Kw = 1.0x10-14


Calculate Kb:

KwKb=Ka·KbKbKb=KwKaKb=1.0×10-141.7×10-9

Kb = 5.88x10-6


Kb is also an equilibrium expression and can be calculated as:

Kb=productsreactants

Solids and liquids are ignored in equilibrium expressions

Kb=C5H5NH3O+C5H5NH+

5.88x10-6=xx0.88-x

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Problem Details

(b) What is the pH of 0.88 M pyridinium chloride, C 5H5NHCl?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Weak Acids concept. If you need more Weak Acids practice, you can also practice Weak Acids practice problems.

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Based on our data, we think this problem is relevant for Professor Davis' class at UCF.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition. You can also practice Chemistry: The Molecular Nature of Matter and Change - Silberberg 8th Edition practice problems.