C5H5NHCl → C5H5NH+ + Cl-
C5H5NH+ → positively charged amine → weak acid
C5H5NH+ + H2O → C5H5NH + H3O+
Kb for C5H5NH = 1.7x10-9
Assuming the reaction is at 25°C: Kw = 1.0x10-14
Kb = 5.88x10-6
Kb is also an equilibrium expression and can be calculated as:
Solids and liquids are ignored in equilibrium expressions
(b) What is the pH of 0.88 M pyridinium chloride, C 5H5NHCl?
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