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The dissociation of (CH3CH2)3NHCl is as follows:
(CH3CH2)3NHCl(aq) → Cl–(aq) + (CH3CH2)3NH+(aq)
[(CH3CH2)3NHCl] = [(CH3CH2)3NH+] = 0.40 M
The hydrolysis of (CH3CH2)3NH+:
(CH3CH2)3NH+(aq) + H2O(l) ⇌ H3O+(aq) + (CH3CH2)3N(aq)
Kb of (CH3CH2)3NH = 5.2 × 10–4
Ka = 1.92 x 10–11
(b) What is the pH of 0.40 M triethylammonium chloride, (CH3CH2)3NHCl?
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