The dissociation of (CH_{3}CH_{2})_{3}NHCl is as follows:

**(CH _{3}CH_{2})_{3}NHCl**

**[(CH _{3}CH_{2})_{3}NHCl] = [(CH_{3}CH_{2})_{3}NH**

The hydrolysis of (CH_{3}CH_{2})_{3}NH^{+}:

**(CH _{3}CH_{2})_{3}NH**

**K _{b} of (CH_{3}CH_{2})_{3}NH = 5.2 × 10^{–4}**

${\mathbf{K}}_{\mathbf{w}}\mathbf{=}{\mathbf{K}}_{\mathbf{a}}{\mathbf{K}}_{\mathbf{b}}\phantom{\rule{0ex}{0ex}}\frac{{\mathbf{K}}_{\mathbf{w}}}{{\mathbf{K}}_{\mathbf{b}}}\mathbf{=}\frac{{\mathbf{K}}_{\mathbf{a}}\overline{){\mathbf{K}}_{\mathbf{b}}}}{\overline{){\mathbf{K}}_{\mathbf{b}}}}\phantom{\rule{0ex}{0ex}}\overline{){{\mathbf{K}}}_{{\mathbf{a}}}{\mathbf{=}}\frac{{\mathbf{K}}_{\mathbf{w}}}{{\mathbf{K}}_{\mathbf{b}}}}\phantom{\rule{0ex}{0ex}}{\mathbf{K}}_{\mathbf{a}}\mathbf{=}\frac{\mathbf{1}\mathbf{.}\mathbf{0}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{14}}}{\mathbf{5}\mathbf{.}\mathbf{2}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{4}}}$

**K _{a} = 1.92 x 10^{–11} **

(b) What is the pH of 0.40 M triethylammonium chloride, (CH_{3}CH_{2})_{3}NHCl?

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