Problem: What is the pH of 0.070 M dimethylamine?

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FREE Expert Solution

Dissociation of dimethylamine in water:

(CH3)2NH(aq) + H2O(l)  OH(aq) + (CH3)2NH2+(aq); Kb5.90 x10–4

ICE table:

The Kb expression for (CH3)2NH is:

$\overline{){{\mathbf{K}}}_{{\mathbf{b}}}{\mathbf{=}}\frac{\mathbf{products}}{\mathbf{reactants}}{\mathbf{=}}\frac{\left[{\left(\mathrm{CH}}_{}}{}}$3)2NH2+][OH-][(CH3)2NH]

Problem Details

What is the pH of 0.070 M dimethylamine?