🤓 Based on our data, we think this question is relevant for Professor Klingler's class at KSU.
The dissociation of HOBr is as follows:
HOBr(aq) + H2O(l) ⇌ H3O+(aq) + OBr–(aq)
Step 1. ICE table and Ka expression.
The Ka expression for HA is:
The pH of a 0.063-M solution of hypobromous acid (HOBr but usually written HBrO) is 4.95. Calculate Ka.
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Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.