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H: FC = 1 – (1 + 0) = 0
left C: FC = 4 – (4+0) = 0
middle C: FC = 4 – (4+0) = 0
right C: FC = 4 – (4+0) = 0
left O: FC = 6 – (2+4) = 0
right O: FC = 6 – (1+6) = -1
Consider the Lewis structure shown below.
Does the Lewis structure depict a neutral molecule or an ion?
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Our tutors have indicated that to solve this problem you will need to apply the Formal Charge concept. You can view video lessons to learn Formal Charge. Or if you need more Formal Charge practice, you can also practice Formal Charge practice problems.
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Based on our data, we think this problem is relevant for Professor Williams' class at ASU.