We’re being asked to determine the empirical formula of a compound composed of Ru and O, given the mass percent of Ru and O.
Recall that the empirical formula is the simplest whole-number ratio formula of a compound.
For this problem, we need to do the following steps:
Step 1: Calculate the mass and moles of Ru and O in the compound.
Step 2: Determine the lowest whole number ratio of Ru and O to get the empirical formula.
You and a partner are asked to complete a lab entitled “Oxides of Ruthenium” that is scheduled to extend over two lab periods. The first lab, which is to be completed by your partner, is devoted to carrying out compositional analysis. In the second lab, you are to determine melting points. Upon going to lab you find two unlabeled vials, one containing a soft yellow substance and the other a black powder. You also find the following notes in your partner’s notebook - Compound 1: 76.0% Ru and 24.0% O (by mass), Compound 2: 61.2% Ru and 38.8% O (by mass).
What is the empirical formula for Compound 1?
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