Problem: The structure of borazine, B3N3H6, is a six-membered ring of alternating B and N atoms. There is one H atom bonded to each B and to each N atom. The molecule is planar.Write a Lewis structure for borazine in which the formal charges on every atom is zero.

FREE Expert Solution

We’re being asked to determine the Lewis structure of borazine B3N3Hwhile the formal charges for each atom should be zero.

To do so, we need to do the following steps:


Step 1: Determine the central atom in the molecule.

Step 2: Calculate the total number of valence electrons present.

Step 3: Draw the Lewis structure for the molecule.

Step 4: Calculate the formal charge for the indicated atom. 


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Problem Details

The structure of borazine, B3N3H6, is a six-membered ring of alternating B and N atoms. There is one H atom bonded to each B and to each N atom. The molecule is planar.

Write a Lewis structure for borazine in which the formal charges on every atom is zero.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Formal Charge concept. You can view video lessons to learn Formal Charge. Or if you need more Formal Charge practice, you can also practice Formal Charge practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Yousif's class at University of Detroit Mercy.