Problem: Consider the following XF4 ions: PF4–, BrF4–, ClF4+, and AlF4–. Which of the ions have more than an octet of electrons around the central atom?

FREE Expert Solution

We’re being asked to determine which among the given compounds is a radical.


Recall that radicals are an exception to the octet rule which occurs when there is an odd number of electrons in an atom.


For this problem, we need to draw the Lewis structure for each compound. 


To do so, we need the following steps:

Step 1: Determine the central atom in this molecule.

Step 2: Calculate the total number of valence electrons present.

Step 3: Draw the Lewis structure for the molecule.



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Problem Details

Consider the following XF4 ions: PF4, BrF4, ClF4+, and AlF4. Which of the ions have more than an octet of electrons around the central atom?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Lewis Dot Structures: Exceptions concept. You can view video lessons to learn Lewis Dot Structures: Exceptions. Or if you need more Lewis Dot Structures: Exceptions practice, you can also practice Lewis Dot Structures: Exceptions practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Kumar's class at Worcester Polytechnic Institute.