One way to measure ionization energies is photoele...

Question

One way to measure ionization energies is photoelectron spectroscopy (PES), a technique based on the photoelectric effect. In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm. A periodic table shows that ionization energy increases moving up the columns and right across the rows. Of those shown, Helium has the largest ionization energy and Cesium has the lowest. Hydrogen is much higher than other group 1 elements. The ionization energy of polonium is 812, Iodine is 1008, and Radon is 1037.

Write an equation that shows the process corresponding to the first ionization energy of Hg.

Jules Bruno · Accepted Answer

We have to write an equation that shows that first ionization energy of mercury.Ionization energy (I. E.) is the energy required to remove an electron from a gaseous atom or ion.• First I.E. corresponds to removing the first valence electron from a neutral atom.[readmore]Since we are removing an electron (e-), it should be on the product side when written in a reaction equation (since the atom is “losing” the electron).When removing an e-:• in a neutral atom → will gain a positive (+) charge become a cation (positively charged ion)• in an ion → will add a positive (+) charge to the current chargeFirst ionization energy → removing the first valence electron from neutral HgHg → Hg+ + e-The equation for the first ionization of mercury is:Hg → Hg+ + e-

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