Ch.7 - Quantum MechanicsWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Using equation E= (hcRH)(1/n2) = (-2.1810-18J)(1/n2), calculate the energy of an electron in the hydrogen atom when n = 6.

Solution: Using equation E= (hcRH)(1/n2) = (-2.1810-18J)(1/n2), calculate the energy of an electron in the hydrogen atom when n = 6.

Problem

Using equation E= (hcRH)(1/n2) = (-2.1810-18J)(1/n2), calculate the energy of an electron in the hydrogen atom when n = 6.

Solution

The energy of an electron in a hydrogen atom is given by:


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The energy level or the shell, in which an electron revolves around the nucleus is termed as n.

In this case: We have n=6.


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