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Problem: Using bond enthalpies in the table, estimate H for the following gas-phase reactions.Average Bond Enthalpies (kJ/mol)Single BondsC-H413N-H391O-H463C-C348N-N163O-O146C-N293N-O201O-F190C-O358N-F272O-Cl203C-F485N-Cl200O-I234C-Cl328N-Br243C-Br276S - H339C-I240H - H436S - F327C - S259H - F567S - Cl253H - Cl431S - Br218Cl - Cl242H - Br366S - S266Br - Br193H - I299Multiple BondsC=C614N=N418O=O495CC839N N941C=N615N=O607C N891C=O799CO1072Estimate H for the reaction.

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Problem Details

Using bond enthalpies in the table, estimate H for the following gas-phase reactions.


Average Bond Enthalpies (kJ/mol)
Single Bonds
C-H413N-H391O-H463
C-C348N-N163O-O146
C-N293N-O201O-F190
C-O358N-F272O-Cl203
C-F485N-Cl200O-I234
C-Cl328N-Br243

C-Br276

S - H

339
C-I240

H - H

436

S - F

327

C - S

259

H - F

567

S - Cl

253


H - Cl

431

S - Br

218

Cl - Cl

242

H - Br

366

S - S

266

Br - Br

193

H - I

299

Multiple Bonds
C=C614N=N418O=O495
CC839N N941

C=N615N=O607

C N891



C=O799



CO1072





Estimate H for the reaction.

The structure of CHBr3 is C single bonded left, above, and below to Br and right H.  CClBr3 is C single bonded left, above, and below to Br and right to Cl.


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