We’re being asked to draw a Lewis structure for BeCl2. We first need to determine the total number of valence electrons present in the molecule:
Group Valence Electrons
Be 2A 1 × 2 e– = 2 e–
Cl 7A 2 × 7 e– = 14 e–
Total: 16 valence e–
In the vapor phase, BeCl2 exists as a discrete molecule.
Draw the Lewis structure of this molecule, using only single bonds.