Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: H2CO3(aq) + H2O(l) ⇌ HCO3–(aq) + H3O+(aq) HCO3–(aq) + H2O(l) ⇌ CO32–(aq) + H3O+(aq) According to the equations above, what is the conjugate base of HCO 3–?  a) H2CO3(aq) b) H2O(l) c) H3O+(aq) d)

Problem

H2CO3(aq) + H2O(l) ⇌ HCO3(aq) + H3O+(aq)

HCO3(aq) + H2O(l) ⇌ CO32–(aq) + H3O+(aq)

According to the equations above, what is the conjugate base of HCO 3

a) H2CO3(aq)

b) H2O(l)

c) H3O+(aq)

d) CO32–(aq)