AgNO_{3}(aq) + HCl(aq) → AgCl(s) + HNO_{3}(aq)

$\overline{)\mathbf{Molarity}\mathbf{}\mathbf{\text{(M)}}\mathbf{=}\frac{\mathbf{mol}}{\mathbf{L}}}$

50.0 mL of 0.100 *M* AgNO_{3}

$\mathbf{mol}\mathbf{}{\mathbf{AgNO}}_{\mathbf{3}}\mathbf{=}\mathbf{50}\mathbf{.}\mathbf{0}\mathbf{}\overline{)\mathbf{mL}}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{L}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}\mathbf{\times}\frac{\mathbf{0}\mathbf{.}\mathbf{100}\mathbf{}\mathbf{mol}}{\overline{)\mathbf{L}}}$

**mol AgNO _{3} = 0.005 mol**

50.0 mL of 0.100 *M* HCl

$\mathbf{mol}\mathbf{}\mathbf{HCl}\mathbf{=}\mathbf{50}\mathbf{.}\mathbf{0}\mathbf{}\overline{)\mathbf{mL}}\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{L}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}\mathbf{\times}\frac{\mathbf{0}\mathbf{.}\mathbf{100}\mathbf{}\mathbf{mol}}{\overline{)\mathbf{L}}}$

**mol HCl = 0.005 mol**

You may want to reference (Pages 271 - 272) Section 6.7 while completing this problem.

The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:

AgNO_{3}(aq) + HCl(aq) → AgCl(s) + HNO_{3}(aq)

When 50.0 mL of 0.100 *M* AgNO_{3} is combined with 50.0 mL of 0.100 *M* HCl in a coffee-cup calorimeter, the temperature changes from 23.40 ^{o}C to 24.21 ^{o}C. Calculate ΔH_{rxn} for the reaction as written. Use 1.00 g/mL as the density of the solution and C = 4.18 J/g°C as the specific heat capacity.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Thermochemical Equation concept. You can view video lessons to learn Thermochemical Equation. Or if you need more Thermochemical Equation practice, you can also practice Thermochemical Equation practice problems.