Problem: A 2.51 g lead weight, initially at 10.6˚C, is submerged in 7.86 g of water at 52.4˚C in an insulated container. What is the final temperature of both the weight and the water at thermal equilibrium? (clead= 0.128 J/(g•oC))

FREE Expert Solution

q=mcT

+qabsorbs heat
–qloses heat


Heat transfer: hot to cold


heat released by water = heat absorbed by lead

– qwater = + qlead


At thermal equilibrium:

▪ final temperature of water = final temperature of lead = final temperature of system

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Problem Details

A 2.51 g lead weight, initially at 10.6˚C, is submerged in 7.86 g of water at 52.4˚C in an insulated container. What is the final temperature of both the weight and the water at thermal equilibrium? (clead= 0.128 J/(g•oC))

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