Problem: The kinetic energy of a rolling billiard ball is given by KE = 1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.7 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 3.8 m/s and then collides head-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.8 m/s. Assume the first billiard ball is the system.Calculate q for the process.

FREE Expert Solution

Step 1

KE = 12mv2KE = 12(0.17 kg)(4.7 ms)2

KE = 1.8777 J


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Problem Details

The kinetic energy of a rolling billiard ball is given by KE = 1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.7 m/s. As it travels, it loses some of its energy as heat. The ball slows down to 3.8 m/s and then collides head-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.8 m/s. Assume the first billiard ball is the system.

Calculate q for the process.

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Our tutors have indicated that to solve this problem you will need to apply the Kinetic Energy of Gases concept. If you need more Kinetic Energy of Gases practice, you can also practice Kinetic Energy of Gases practice problems.