Problem: We pack two identical coolers for a picnic, placing 24 12-ounce soft drinks and five pounds of ice in each. However, the drinks that we put into cooler A were refrigerated for several hours before they were packed in the cooler, while the drinks that we put into cooler B were at room temperature. When we open the two coolers three hours later, most of the ice in cooler A is still present, while nearly all of the ice in cooler B has melted.Explain this difference.

🤓 Based on our data, we think this question is relevant for Professor Anliker's class at IUPUI.

FREE Expert Solution

Heat lost or gained is directly proportional to the change in temperature , ΔT:

  • higher ΔT → bigger heat gain
  • lower ΔT → smaller heat gain


Melting → absorbs heat 


In each cooler: 

  • heat gained by ice = heat lost by drinks
  • +qice = -qdrinks

Melting temperature of ice = 0°C

Room temperature = ~25°C

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Problem Details

We pack two identical coolers for a picnic, placing 24 12-ounce soft drinks and five pounds of ice in each. However, the drinks that we put into cooler A were refrigerated for several hours before they were packed in the cooler, while the drinks that we put into cooler B were at room temperature. When we open the two coolers three hours later, most of the ice in cooler A is still present, while nearly all of the ice in cooler B has melted.

Explain this difference.

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Calorimetry concept. You can view video lessons to learn Calorimetry. Or if you need more Calorimetry practice, you can also practice Calorimetry practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Anliker's class at IUPUI.