We are asked to calculate the ΔH of sublimation of I2(s)
We can use the following equation to solve for ΔH˚rxn:
Note that we need to multiply each ΔH˚f by the stoichiometric coefficient since ΔH˚f is in kJ/mol.
Also, note that ΔH˚f for elements in their standard state is 0.
ΔH˚f TiI3(s) = –328 kJ/mol
ΔH˚f Ti(s) = 0 kJ/mol (standard state)
We also need to convert ΔH˚rxn from kJ/mol to J/ mol so our units remain consistent.
Ti(s) + 3 I 2(g) → 2 TiI3(s)
The ΔHf˚ of TiI3(s) is –328 kJ/mol and the ΔH˚ for the reaction Ti(s) + 3 I 2(g) → 2 TiI3(s) for the reaction is –839 kJ. Calculate the ΔH of sublimation of I2(s), which is a solid at 25˚C.
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