Step 1: The total number of valence electrons present in N2O is:
Group Valence Electrons
N 5A 2 × 5 e– = 10 e–
O 6A 1 × 6 e– = 6 e–
Total: 16 valence e–
Step 2: The complete Lewis structure for N2O (exist as resonance structures).
Resonance structures of N2O:
Assign formal charges to each atom in the resonance forms of N2O.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Lewis Dot Structure: Formal Charge concept. If you need more Lewis Dot Structure: Formal Charge practice, you can also practice Lewis Dot Structure: Formal Charge practice problems.
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Based on our data, we think this problem is relevant for Professor Murphy's class at BU.