Problem: An electron in the n = 6 level of the hydrogen atom relaxes to a lower energy level, emitting light of λ = 410 nm. { m ; m nmFind the principal level to which the electron relaxed.

FREE Expert Solution

We’re being asked to calculate for the principal level to which the electron relaxed.


We’re going to use the Balmer Equation which relates wavelengths to a photon’s electronic transitions.

1λ=RZ21n2final-1n2initial

λ = wavelength, m
R = Rydberg constant = 1.097x107 m-1 
Z = atomic number of the element
ninitial = initial energy level
nfinal = final energy level


Calculate the final energy level (nfinal):

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Problem Details

An electron in the n = 6 level of the hydrogen atom relaxes to a lower energy level, emitting light of λ = 410 nm. Find the principal level to which the electron relaxed.


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