# Problem: Write a hybridization and bonding scheme for each molecule. Label all bonds in NF3.

###### FREE Expert Solution

Step 1: Determine the central atom in this molecule.

• N less electronegative atom than F → central atom

Step 2: Calculate the total number of valence electrons present.

NF3:

Group               Valence Electrons

N         5A                   1 × 5 e = 5 e

F          7A                   3 × 7 e = 21 e

Total:  26 valence e

Step 3: Draw the Lewis Structure for the molecule

•  prefers to have 1 bond and complete octet
• surround N with three F atoms
• Distribute extra electrons in each of the F atoms (since they prefer to have complete octet)
• if there are remaining electrons, place it in the central atom Step 4: Determine the hybridization of the central atom.

• There are 4 domains or groups around central element N:
• 3 F atoms + 1 lone pair = 4 domains
• It will need 4 orbitals to accommodate these 4 groups.

Orbitals that can be used by the central atom:

Subshell                   Total # of orbitals

s           _                1 orbital

p       _ _ _              3 orbitals

d        _ _ _ _ _        5 orbitals

• 1 s orbital + 3 p orbitals = 4 orbitals (4 groups) ###### Problem Details

Write a hybridization and bonding scheme for each molecule. Label all bonds in NF3.